01 - Introduction to trajectories Analysis - OMT

01 - Introduction to trajectories Analysis - OMT

🕒 17:30: Problem solved in class (see iPad)

Imagine three friends who want to take a long trip using a tandem bicycle for two persons. Because the bike riders travel at 20 km/h, independent of the number of riders, and all three persons walk at 4 km/h, they proceed as follows:

  • To start the journey, friends “A” and “B” ride the bicycle and friend “C” walks.
  • After a while, friend “A” drops off friend “B” who starts walking and “A” rides the bicycle alone in reverse direction.
  • When “A” and “C” meet, they turn the bicycle and ride forward until they catch up with “B”.
    At that moment, the 3 friends have completed a basic cycle of their strategy, which they then repeat a number of times until they reach their destination. Could you determine their average travel speed?

Solution: vm=10kmh

Introduction to trajectories Analysis 2024-10-01 18.15.47.excalidraw.png
%%🖋 Edit in Excalidraw%%

Trajectories of a traffic stream on a time-space diagram

When we work with time and space we use coordinated axis, with time (t) on the horizontal axis and space (x) on the vertical axis.

Introduction to trajectories Analysis 2024-10-01 17.52.02.excalidraw.png

This visualization allows to have all the main parameters readily available:

Velocity:

v=xt=x˙

Acceleration:

a=2xt2=x¨

Introduction to trajectories Analysis 2024-10-01 17.59.18.excalidraw.png

The graph shows a possible trajectory of an elevator that stops at floor 3 and 5.

Scheduling

We want to figure out the capacity of a rail line (single rail)

We have a train traveling from A to B at constant speed Vtech. We neglect accelerations.

Capacity is a flow: qmax[vehh]

flow

It's the number of passengers or vehicles or expeditions per hour
q

Introduction to trajectories Analysis 2024-10-01 18.20.11.excalidraw.png

Dwell time is the time taken for passengers to board and un-board.
Headway: (h)

q=1h

then:

qmax=1hmin

We can increase capacity of the diagram above in different ways:

Introduction to trajectories Analysis 2024-10-01 18.40.19.excalidraw.png

Constructing trajectories

Introduction to trajectories Analysis 2024-10-07 17.03.13.excalidraw.png

Traffic stream properties

Introduction to trajectories Analysis 2024-10-07 17.09.52.excalidraw.png

Flow

We can define the flow - MACROscopic variable:

q=mT

where:

Can be written as:

q=mi=1mhi

also

q=11mi=1mhi=1h

Flow is equal to the inverse of the average headway:

The headway is considered a microscopic variable.

Spacing

s[m]

If we count the number (n) of vehicles in a stretch of length L, we obtain the DENSITY:

k=nL[vehspac],[vehkm]

And can also write:

k=11nj=1nsj=1s

Speed

Introduction to trajectories Analysis 2024-10-07 17.19.26.excalidraw.png

Introduction to trajectories Analysis 2024-10-07 17.27.14.excalidraw.png

The difference is that in one case we're measuring

VtVs

Let i be a family of vehicle (ie traveling at the same speed)

Vt=imiViimi

If I multiply everything by 1T:

Vt=1TimiVi1Timi=iqiViqtot

For spatial:

Vs=1LjnjVj1Ljnj=ikjVjktot

Fundamental equation of traffic

Stationary traffic

You can measure any value anywhere and it's always the same.

The only way is to have parallel trajectories that are equidistant

Introduction to trajectories Analysis 2024-10-07 17.38.34.excalidraw.png

q=mTk=nLqk=LT=V

then

q=kV

This is true for stationary traffic.
Also:

Vs=Vt

It's also true for any kind of traffic:

q=kVs

❗❗❗❗❗❗❗❗❗❗❗❗
❗❗❗ COMPLETARE ❗❗❗
❗❗❗❗❗❗❗❗❗❗❗

q=iq.=ikiVikkq=k[kiVik]